Problem 6 In each of Exercises 1–10, mat... [FREE SOLUTION] (2024)

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Chapter 2: Problem 6

In each of Exercises 1–10, match the question with the most appropriatetranslation from the column on the right. Some choices are used more thanonce. _____23 is what percent of \(57 ?\) $$ a) a=(0.57) 23\quad b) 57=0.23 y \quad c) n 23=57\quad d) n 57=23\quad e) 23=0.57 y\quad f) a=(0.23) 57\quad $$

Short Answer

Expert verified

e) 23=0.57 y

Step by step solution

02

Set up the equation

To find out what percent 23 is of 57, we use the formula: \[ \text{Percentage} = \frac{\text{part}}{\text{whole}} \times 100 \times 100 \tag{1} \]

03

Substitute the values

Here, the part is 23 and the whole is 57. Substitute these values into equation (1): \[ \text{Percentage} = \frac{23}{57} \times 100 \ \text{Percentage} = \frac{23}{57} \times 100 \]

04

Compare with the given choices

We need to match this with the given options. The corresponding choice should be in the form: \[23=0.23 \times y\]

05

Identify the correct choice

Among the given options, e) 23 = 0.57 y is the correct basic format. Therefore, the translation should match e).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentages

Percentages are a way to express a number as a fraction of 100. They are denoted using the percent symbol \(%\). For example, 50% is the same as saying 50 out of 100 or 0.50. When trying to find out what percent one number is of another, we use a simple formula:
\[ \text{Percentage} = \frac{\text{part}}{\text{whole}} \times 100 \]
Here, the 'part' is the smaller value or the value we are focused on, and the 'whole' is the larger value or the total amount. This formula helps simplify percentage problems, whether in a classroom setting or everyday life.
For instance, if you need to find what percent 23 is of 57, identify 23 as the part and 57 as the whole. Then apply the formula to get the percentage. This straightforward method makes understanding percentages much simpler.

Equation Setup

Setting up the correct equation is crucial for solving algebra word problems. In percentage problems, you often translate a word problem into a math equation. This involves identifying the variables and constants involved and structuring them correctly.
For the problem '23 is what percent of 57?', we start by setting up an equation using the percentage formula. Knowing that:
\[ \text{Percentage} = \frac{23}{57} \times 100 \]
This equation allows us to identify the variables and isolate what we need to solve for. In this case, we substitute 23 as the 'part' and 57 as the 'whole'. This setup forms the basis for solving the equation. It ensures accuracy and helps lay a solid foundation for finding the solution.
Correctly setting up equations is essential in algebra as it directly leads to finding the right answers efficiently and accurately.

Algebraic Expressions

Algebraic expressions are mathematical phrases that can include numbers, variables, and operation symbols. In percentage word problems, these expressions are used to represent the parts of our problem numerically and symbolically.
Take the exercise '23 is what percent of 57?' After setting up the equation, our algebraic expression is:
\[ 23 = 0.57 \times y \]
In general, for any percentage word problem, you may re-write it as:
\[ \text{part} = \left( \frac{\text{part}}{\text{whole}} \right) \times 100 \]
Using this algebraic expression, you can easily manipulate and solve for the variable you're interested in, such as the percentage (\(y\)) in this case. Understanding and being able to craft algebraic expressions is key in translating word problems into solvable equations, which is a fundamental skill in algebra.

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Problem 6 In each of Exercises 1–10, mat... [FREE SOLUTION] (3)

Most popular questions from this chapter

Use an inequality and the five-step process to solve each problem. In the last weeks before the yearly Topsfield Weigh In, heavyweight pumpkinsgain about 26 lb per day. Charlotte's heaviest pumpkin weighs 532 lb onSeptember \(5 .\) For what dates will its weight exceed 818 lb?Write a problem for a classmate to solve. Devise it so that the problem can betranslated to the equation \(x+(x+2)+(x+4)=375\)Translate to an inequality. To rent a car, a driver must have a minimum of 5 years of driving experience.Use an inequality and the five-step process to solve each problem. One side of a triangle is \(2 \mathrm{cm}\) shorter than the base. The otherside is \(3 \mathrm{cm}\) longer than the base. What lengths of the base willallow the perimeter to be greater than \(19 \mathrm{cm} ?\)
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Problem 6 In each of Exercises 1–10, mat... [FREE SOLUTION] (2024)

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